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Zadatak 0016

Test: MPo5BGIII_002

 

Reši jednačine:                a) \(x-2,8=3\frac{1}{4}\);                      b) \(\left ( 6\frac{7}{10}-x \right )+1\frac{1}{2}=2\).

Rešenje:


 

a)

\( x=3\frac{1}{4}+2\frac{8:2}{10:2}\)

 

\( x=3\frac{1}{4}+2\frac{4}{5}\)

 

\( x=3\frac{1\cdot 5}{4\cdot 5}+2\frac{4\cdot 4}{5\cdot 4}\)

 

\( x=5\frac{21}{20}=6\frac{1}{20}\).

 

b)

 \(\left ( 6\frac{7}{10}-x \right )=2-1\frac{1}{2}\)

 

 \(6\frac{7}{10}-x =1\frac{2}{2}-1\frac{1}{2}\)

 

 \(x=6\frac{7}{10}-\frac{1}{2}\)

 

 \(x=6\frac{7}{10}-\frac{1\cdot 5}{2\cdot 5}\)

 

 \(x=6\frac{2}{10}\)

 

\(x=6\frac{2:2}{10:2}=6\frac{1}{5}\).

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